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In triangle ABC, if the lengths of sides a and c are 8 centimeters and 16 centimeters, respectively, and the measure of angle c is 35, what is the measure of angle a to two decimal places?

User BennyP
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2 Answers

3 votes
Hello,

a=8, c=16, C=35°

sin A/a=SIN C/c (law of sinus)
==> sin A=a/c* sin C=8*16*sin35°=0,286788....
==>A=16,665768...°≈16.66°


User Jonathan Lin
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4 votes

Answer:

The approximate measure of angle is 16.67°.

Explanation:

Given,

Triangle ABC in which,

Side a = 8 cm, ( side BC )

Side c = 16 cm ( side AB ),

Also, m∠C = 35°,

By the law of sine,


(sin A)/(sin C)=(BC)/(AB)

By substituting the values,


(sin A)/(sin 35^(\circ))=(8)/(16)


sin A = (8* sin 35^(\circ))/(16)=0.293892626146


\implies m\angle A=16.665768674\approx 16.67^(\circ)

User Jwwnz
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