Question

Which is the factorization of 8x2 13x – 6? (8x – 3)(x 2) (x – 6)(8x 1) (2x – 2)(4x 3) (4x – 1)(2x 6)

Answer 1

so than there are

8x^2 +13x -6 = (8x-3)(x+2)

hope this will help you

Answer 2

we have

`8x^2+13x - 6`

Equate the function to zero

`8x^2+13x - 6=0`

Group terms that contain the same variable, and move the constant to the opposite side of the equation

`8x^2+13x = 6`

Factor the leading coefficient

`8(x^2+(13)/(8)x) = 6`

Complete the square. Remember to balance the equation by adding the same constants to each side.

`8(x^2+(13)/(8)x) = 6`

`8(x^2+(13)/(8)x+(169)/(256)) = 6 +(169)/(32) \\ \\ 8(x+(13)/(16) )^(2) =(361)/(32) \\ \\ (x+(13)/(16) )^(2) =(361)/(256)\\ \\ (x+(13)/(16) ) =(+/-)\sqrt{(361)/(256)} \\ \\ (x+(13)/(16) ) =(+/-)(19)/(16) \\ \\ x1=-(13)/(16) +(19)/(16) =(6)/(16)\\ \\ x2=-(13)/(16) -(19)/(16)=-2`

the factorization is equal to

`8*(x-(6)/(16) )*(x+2)=(8x-3)*(x+2)`

therefore

the answer is

`(8x-3)*(x+2)`