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Determine the empirical formula of H 3.66%; P 37.8%; O 58.5%
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Determine the empirical formula of H 3.66%; P 37.8%; O 58.5%

User Lloyd Powell
by
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1 Answer

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We have atomic masses of: (omit units)
O=16
H=1
P=39
So:
O=58,5/16=3,65/1,21=3,01≈3
H=3,66/1=3,66/1.21=3,02≈3
P=37,8/31=1,21/1,21=1
So the empiric formula is:
H₃PO₃
User Roman Gudkov
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