450,394 views
41 votes
41 votes
HW Score: 50%, 2 of 4 point

O Points: 0 of 1
A city council consists of five Democrats and seven Republicans. If a committee of six people is selected, find the probability of selecting two Democrats and four Republicans.
Homework: Section 11.5
(Type a fraction. Simplify your answer.)
Help me solve this View an example Get more help.
Question 3, 11.5.13 >
CE

User Dhruv Ramani
by
2.7k points

1 Answer

7 votes
7 votes

Step 1

Given; A city council consists of five Democrats and seven Republicans. If a committee of six people is selected, find the probability of selecting two Democrats and four Republicans.

Step 2

First, we have to find how many ways to choose 2 democrats from 5 which is;


5_(c_2)

and 4 republicans from 7 which is;


7_(c_4)

Then just multiply the two together to get the number of ways the two can be combined


5_(c_2)=(5!)/(2(5-2)!)=10
7_(c_4)=(7!)/(4!(7-4)!)=35

Answer;


\begin{gathered} 5_(c_2)*7_(c_4)=10*35=350ways \\ P=(350)/(924)=(25)/(66) \end{gathered}

User Jacob CUI
by
2.8k points