Question

Kirsten built a rectangular corral with a fence on three sides.A side of the barn served as a short side od the corral.She used 130 m of fencing . The length of the corral was 20 m longer than the width . Find the dimensions of the corral. Choices for the width : 25, 30 , 35 EXPLAIN

Answer 1

L = W + 20
2L + W = 130

Solve that system with each of the width values. Aka: plug in each w and solve for the length. Whichever w value gets the same L value for both equations is the answer.

Answer 2

Answer: Second option is correct.

Explanation:

Since we have given that

Let the width of corral be 'w'.

Let the length of corral be 'w+20'

Perimeter of corral = 130 m

As we know the formula for "Perimeter":

`Perimeter=2l+w\\\\130=2(w+20)+w\\\\130=2w+40+w\\\\130=3w+40\\\\130-40=3w\\\\90=3w\\\\(90)/(3)=w\\\\w=30\ m`

so, width of corral = 30 m

Length of corral = 30+20 = 50 m

Hence, Second option is correct.