Question

The endpoints of EF¯¯¯¯¯ are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of EF¯¯¯¯¯? (xF2,yF2) (xE2,yE2) (xE+xF2,yE+yF2) (xE+xF2,yE+yF2)

Answer 1

Answer: The correct option is (D)
`\left((xE+xF)/(2),(yE+yF)/(2)\right).`

Step-by-step explanation: Given that the co-ordiantes of the end-points of segment EF are E(xE, yE) and F(xF, yF) respectively.

To find the co-ordinates of the mid-point of EF.

We know that

the co-ordinates of the mid-point of a line segment with end-points A(a, b) and B(c, d) are given by

`\left((a+c)/(2),(b+d)/(2)\right).`

Therefore, the co-ordinates of the mid-point of segment Sf will be

`\left((xE+xF)/(2),(yE+yF)/(2)\right).`

Thus, (D) is the correct option.

Answer 2

The coordinates of the midpoint of EF are:
M (
`(xE+xF)/(2), (yE+yF)/(2)` )