Question

At most, Alana can spend $40 on carnival tickets. Ride tickets cost $4 each, and food tickets cost $2 each. Alana buys at least 16 tickets. The system of inequalities represents the number of ride tickets, r, and the number of food tickets, f, she buys.

r + f ≥ 16

4r + 2f ≤ 40



What is the maximum number of ride tickets she can buy?

4
6
10
12

Answer 1

A

Explanation:

4 on EDGE

just did it

Answer 2

We can let r be the number of food tickets and f be the number of food tickets. Since Alana can spend at most $40, that means the total of price bought for r and f must be less than or equal to $40. In addition, since Alana buys at least 16 tickets, this also means that the total of r and f is 16. Mathematically, we have these inequalities: (1) 4r + 2f ≤ 40 and (2) r + f ≥ 16 Multiplying -2 in (2), we have 4r + 2f ≤ 40 -2r - 2f ≤ 32 Adding both inequalities, 2r ≤ 8 r ≤ 4 Since r must be less than or equal to 4.Thus the answer is A.