Answer: 11.4 cal
Explanation:
The amount of heat absorbed by the sample is given by:
Q = m c ΔT
where, m is the mass, c is the specific heat and ΔT is the change in temperature.
Specific heat is the amount of heat required to raise the temperature of 1 g of mass by 1°C.
⇒Q = 10.0 g × 0.057 cal/g °C × 20.0° C = 11.4 cal
Thus, 11.4 calories would be absorbed by the sample of silver.