Question

If the endpoints of line AB have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of line AB?

Answer 1

Answer and Step-by-step explanation:

Answer:

The cross section will be an isosceles triangle

Explanation:

The image of the inquiry in the joined figure N 1

we realize that

On the off chance that a plane goes through the pivot of revolution of the cone, at that point the resultant cross-area will be a triangle with one vertex as the vertex of the cone and the different sides of the triangle through the vertex A will be equivalent.

Where the base of the triangle will be equivalent to the breadth of the round base of cone and the two compatible sides of triangle will be equivalent to the inclination tallness of the cone

hence

The cross segment will be an isosceles triangle

Answer 2

To do this we need to now the equation and our number.
The midpoint equation is=
((x1+x2)/2), ((y1+y2)/2)
And our point are=
A= 9,8
B=-1,-2
Now we just put our numbers in place.
((9+ -1)/2), ((8+ -2)/2)
(8/2), (6/2)
(4,3)
So your mid point is= (4,3)