71.9k views
1 vote
Find the answer to
(x + y + 2)( y + 1)

User Avez Raj
by
6.6k points

2 Answers

2 votes
I assume the question asks to expand the expression to individual terms.
There are different ways to approach this, all based on FOIL or similar methods.
I prefer to split it into two parts, as follows:
(x+y+2)(y+1)
=x(y+1)+(y+2)(y+1)
=xy+x+y^2+3y+2
User Moritzrupp
by
6.9k points
3 votes

Answer:
(x + y + 2)( y + 1)=xy+y^2+3y+x+2

Explanation:

The given expression:
(x + y + 2)( y + 1)

Using left distributive property:


a(b+c)=ab+ac, where a, b, c are any arbitrary expressions.


\Rightarrow (x + y + 2)( y + 1)=(x+y+2)y+(x+y+2)(1)\\\\=

Using right distributive property:


(b+c)a=ba+ca, where a, b, c are any arbitrary expressions.


\Rightarrow(x+y+2)y+(x+y+2)(1)=xy+y^2+2y+x+y+2=xy+y^2+3y+x+2

Hence,
(x + y + 2)( y + 1)=xy+y^2+3y+x+2

User Ashwintastic
by
6.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.