Question

Use the discriminant to find the number of real solutions of the equation 3x2 – 5x + 4 = 0. Show your work.

Answer 1

3x^2 - 5x + 4 = 0
a=3 b=-5 c=4

D = b^2 - 4ac
D = (-5)^2 - 4(3)(4)
D = -23

therefore D < 0 which means no real roots.

Answer 2

two imaginary solutions. No real solutions

Explanation:

Use the discriminant to find the number of real solutions of the equation

3x^2 – 5x + 4 = 0

To find discriminant we use formula

D= b^2 - 4ac

D =0 , 1 real solution

D>0, 2 real solutions

D<0, 2 imaginary solutions

3x^2 – 5x + 4 = 0

from the given equation, a= 3 , b= -5 and c= 4

D= b^2 - 4ac= (-5)^2 - 4(3)(4)= 25- 48= -23

D is negative that means D<0

So , two imaginary solutions