Question

What is the product of (2p + 7)(3p2 + 4p – 3)?

6p3 + 29p2 – 34p + 21
6p3 + 29p2 – 22p + 21
6p3 + 29p2 + 22p – 21
6p3 + 29p2 + 34p – 21

Answer 1

C. 6p3 + 29p2 + 22p - 21
Hope this helps!!!

Answer 2

Answer:
`6p^3 + 29p^2 + 22p – 21`

Explanation:

The given expression :
`(2p + 7)(3p^2 + 4p - 3)`

To find the product, we need to use the distributive property.

The distributive property is given by :-

`a(b+c)=ab+ac`

Then , the product will become:

`(2p + 7)3p^2 + (2p + 7)4p - (2p + 7)3\\\\=\\\\=(2p*3p^2 + 7*3p^2)+(2p*4p + 7*4p)-(2p*3 + 7*3)\\\\=6p^(2+1)+21p^2+8p^(1+1)+28p-6p-21........\text{Since }a^ma^n=a^(m+n)\\\\=6p^3+21p^2+8p^2+22p-21\\\\=6p^3 + 29p^2 + 22p - 21`