Question

An airplane flies due north at 100 m/s through a 30 m/s cross wind blowing from the east to the west. Determine the resultant velocity of the airplane.

Answer 1

Vf=√30²+100²
Vf=104 m/s

|Ф|=tan inverse of |100÷30|
Ф= 73 degrees

Therefore the resulting velocity of the airplaine is 104 m/s [ 73 degrees N of W]

Answer 2

The resultant velocity of the airplane is 104.4 m/s.

Step-by-step explanation:

It is given that,

Velocity of airplane,
`v_1=100\ m/s` (due north)

Velocity of wind,
`v_2=30\ m/s` (east to the west)

We need to find the resultant velocity of the airplane. The resultant velocity is given by :

`v=√(v_1^2+v_2^2)`

`v=√((100)^2+(30)^2)`

v = 104.4 m/s

So, the resultant velocity of the airplane is 104.4 m/s. Hence, this is the required solution.