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11. A sample of gas at 298 K has a volume of 11 L and exerts a pressure of

660 mm Hg. How many moles of gas are in the sample?
O 0.39 mol
O
3.9 mol
09.3 mol
0
87 mol

User Anshoo
by
2.5k points

1 Answer

9 votes

Answer:

0.39 mol

Step-by-step explanation:

Step 1: Given and required data

  • Temperature of the gas (T): 298 K
  • Volume of the container (V): 11 L
  • Pressure of the gas (P): 660 mmHg
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Convert "P" to atm

We will use the conversion factor 1 atm = 760 mmHg.

660 mmHg × 1 atm/760 mmHg = 0.868 atm

Step 3: Calculate the moles of gas (n)

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.868 atm × 11 L/(0.0821 atm.L/mol.K) × 298 K

n = 0.39 mol

User Sandra K
by
3.7k points