Answer:
0.39 mol
Step-by-step explanation:
Step 1: Given and required data
- Temperature of the gas (T): 298 K
- Volume of the container (V): 11 L
- Pressure of the gas (P): 660 mmHg
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Convert "P" to atm
We will use the conversion factor 1 atm = 760 mmHg.
660 mmHg × 1 atm/760 mmHg = 0.868 atm
Step 3: Calculate the moles of gas (n)
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 0.868 atm × 11 L/(0.0821 atm.L/mol.K) × 298 K
n = 0.39 mol