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Find the temperature from 150ml cylinder containing 0.75 moles gas at 153kpa.

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To find the temperature in the problem, we apply the ideal gas law, PV=nRT where R=8.314 Pam3/mol K. Substituting the given, T= 153,000 Pa*1.5x10^-4 m3/ [(0.75 mol)(8.314 Pam3/mol K)]. The temperature is equal to 3.68 kelvin.
User Kenneth De Win
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