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What are the real imaginary solutions of the polynomial equation?
x^3=216

1 Answer

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When you look at it, you would wonder why this equation is considered to be a polynomial where in fact there is only one factor. The only reason to explain this is that the other factors have zero as the coefficient. On another note, to answer this problem, we need to get the cube root of 216 which is 6, which is also the answer to this problem. 
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