Question

A solution of ammonia and water contains 1.80×1025 water molecules and 7.00×1024 ammonia molecules. How many total hydrogen atoms are in this solution?

Answer 1

1 water molecule contains 2H atoms H atoms in 4.20*10^25 water molecules = 8.4*10^25 H atoms 1 NH3 molecule contains 3 H atoms H atoms in 6.00*10^24 NH3 atoms = 3*6.00*10^24 = 1.8*10^16 H atoms.

Total H atoms = 8.4*10^25 + 1.8*10^25 = 1.02*10^16 H atoms

Answer 2

6.40x10²⁵ hydrogen atoms

Step-by-step explanation:

The solution contains:

• 1.80x10²⁵ water molecules (H₂O)
• 7.00x10²⁴ ammonia molecules (NH₄)

We need to calculate the total of hydrogen atoms (H) in the solution.

• Each water molecule (H₂O) has 2 hydrogen atoms
• Each ammonia molecule (NH₄) has 4 hydrogen atoms

Lets now calculate the number of hydrogen atoms in the solution:

total H atoms = (H atoms in water molecules) + (H atoms in ammonia molecules)

total H atoms = (2 x 1.80x10²⁵) + (4 x 7.00x10²⁴) =

total H atoms = 3.60x10²⁵ + 2.80x10²⁵ = 6.40x10²⁵