Final answer:
The sample contains 0.501 moles of NH4NO3.
Step-by-step explanation:
The mass of the sample of ammonium nitrate is given as 40.10 g and the molar mass of NH4NO3 is 80.0432 g/mol.
To find the number of moles of NH4NO3 in the sample, we can use the formula:
moles = mass / molar mass
Plugging in the given values, we have:
moles = 40.10 g / 80.0432 g/mol = 0.501 mol
Therefore, the sample contains 0.501 moles of NH4NO3 (to the correct number of significant digits).