Question

A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form?

A=–n2 + 3n + 5
B=n2 + 6n + 1
C=2n2 + 6n – 1
D=3n2 + 5

Answer 1

If you would like to find AB - C in simplest form, you can do this using the following steps:

A = n
B = 2n + 6
C = n^2 - 1

AB - C = n * (2n + 6) - (n^2 - 1) = 2n^2 + 6n - n^2 + 1 = n^2 + 6n + 1

The correct result would be B=n2 + 6n + 1.

Answer 2

`AB-C=n^(2) +6n +1`

Explanation:

Given :

`A = n`

`B=2n+6`

`C=n^(2) -1`

To Find: AB-C

Solution:

Since A=n

B=2n+6

So,
`AB=2n^(2) +6n`

Now since
`C=n^(2) -1`

Thus
`AB-C=2n^(2) +6n-(n^(2) -1)`

⇒
`AB-C=2n^(2) +6n-n^(2) +1`

⇒
`AB-C=n^(2) +6n +1`

Thus option B is correct .