Question

A gas at 255 kilopascals and 45°C has an initial volume of 2.00L. The pressure of the gas increases to 805 kilopascals as the temperature is raised to 255°C. What will be the new volume?

1.05 liters
2.28 liters
1.25 liters
0.44 liters
1.50 liters

Answer 1

Answer : The correct option is, (a) 1.05 liters

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 255 kpa

`P_2` = final pressure of gas = 805 kpa

`V_1` = initial volume of gas = 2 L

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`45^oC=273+45=318K`

`T_2` = final temperature of gas =
`255^oC=273+255=528K`

Now put all the given values in the above equation, we get the final volume of gas.

`(255kpa* 2L)/(318K)=(805kpa* V_2)/(528K)`

`V_2=1.05L`

Therefore, the final or new volume of gas will be, 1.05 liters