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What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?

What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?-example-1
User Diandrea
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1 Answer

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The radioactive half-life is given by:


T_(1/2)=(ln(2))/(\lambda)

Where:


\begin{gathered} T_(1/2)=299*10^(-9)s \\ so: \\ \lambda=(ln(2))/(299*10^(-9)) \\ \lambda=2.32*10^6s \end{gathered}

User Snowburnt
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