330,028 views
22 votes
22 votes
What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?

What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?-example-1
User Diandrea
by
3.1k points

1 Answer

11 votes
11 votes

The radioactive half-life is given by:


T_(1/2)=(ln(2))/(\lambda)

Where:


\begin{gathered} T_(1/2)=299*10^(-9)s \\ so: \\ \lambda=(ln(2))/(299*10^(-9)) \\ \lambda=2.32*10^6s \end{gathered}

User Snowburnt
by
2.6k points