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Calculate the youngs modulus for the material of the wire

Calculate the youngs modulus for the material of the wire-example-1
User Daniel McLaury
by
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1 Answer

14 votes
14 votes

First, plot the data shown as points.

The points are (0,0), (1.4, 10), (2.8, 20), (4.2, 30), (4.9, 35), (5.8, 40), and (8, 45).

The graph shows a proportional part (a straight line) and a curvy part. So, the limit of proportionality is shown at the end of the straight line segment. The image below shows this limit.

The gradient of the straight-line portion refers to the slope. Let's use the points (1.4, 10) and (2.8, 20).


m=(y_2-y_1)/(x_2-x_1)=(20-10)/(2.8-1.4)=(10)/(1.4)\approx7.14

Therefore, the gradient is 7.14.

The Young modulus formula is


E=((F)/(A))/((\Delta l)/(l))

Let's use the greater force and the greater extension.


E=((45N)/(7*10^(-8)m^2))/((8*10^(-3)m)/(2m))=1.6*10^(11)

Therefore, Young Modulus is 1.6x10^11.

Calculate the youngs modulus for the material of the wire-example-1
Calculate the youngs modulus for the material of the wire-example-2
User Kristofersen
by
2.6k points