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Let's f(x)=2x-5 . Write a function k whose graph is a rotation of f(x)about (0,-5) by a factor of 1/2.

User Barrast
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1 Answer

29 votes
29 votes

f(x)=2x-5

the graph

the new line must pass through the point so we can just multiply x by the factor


\begin{gathered} k(x)=2x((1)/(2))-5 \\ k(x)=x-5 \end{gathered}

red is the rotation and the green line is the solution (x-5)

Let's f(x)=2x-5 . Write a function k whose graph is a rotation of f(x)about (0,-5) by-example-1
Let's f(x)=2x-5 . Write a function k whose graph is a rotation of f(x)about (0,-5) by-example-2
User AlexG
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