Question

A gas sample is heated from -20.0 C to 57.0 C and the volume is increased from 2.00 L to 4.50 L If the initial pressure is .140 atm, what’s the final pressure?

Answer 1

0.081atm

Explanations:

According to general gas equation expressed as:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where:

• P1 and P2 are the ,initial and final pressure

,

• V1 and V2 are the ,initial and final volume

,

• T1 and T2 are the i,nitial and final temperature

Given the following parameters

`\begin{gathered} V_1=2.00L \\ V_2=4.50L \\ T_1=-20.0^0C+273=253K \\ T_2=57^0C+273=330K \\ P_1=0.140atm \end{gathered}`

Required

Final Pressure P2

Substitute the given parameters into the formula

`P_2=(P_1V_1T_2)/(V_2T_1)`

Substitute the given following parameters into the formula

`\begin{gathered} P_2=(0.14*2.00L*330K)/(4.50L*253K) \\ P_2=(92.4)/(1138.5) \\ P_2=0.081atm \end{gathered}`

Hence the final pressure of the gas sample is 0.081atm