Question

A school has collected data about student interest in extracurricular activities. They calculated that P(Baseball) = 0.5, P(Music) = 0.6, and P(Baseball and Music) = 0.7. Determine the P(Baseball or Music). a0.5 b0.4 c0.3 d0.2

Answer 1

According to the given situation, we have to use the following formula to find the answer to this question.

`P(B\cup M)=P(B)+P(M)-P(B\cap M)`

In this case, P(B) is the probability of the students who like baseball, P(M) the probability of the students who like music and P(B∩M) is the intersection, it means, the probability of the students who like both. The probability of the students who like baseball or music is represented by P(B∪M) and this is what we are going to find.

Replace for the given values and find P(B∪M):

`P(B\cup M)=0.5+0.6-0.7=0.4`

The probability that students like baseball or music is 0.4.

The correct answer is b.