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Simplify. 5x^3/(7x^3+x^4)

5/7+x; where x is not equal to 0, -7
5/7+x; where x is not equal to -7
5/7x; where x is not equal to 0
5/7

User Akeen
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Hello,


(5 x^(3) )/(7 x^(3) + x^(4) ) = (5 x^(3) )/(x^(3)(7+x) )=\frac{5} {7+x}

Answer Almost A with parenthesis

5/(7+x)


User Cdesrosiers
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