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What is the equation of the line perpendicular to 2x − 5y = −35 that contains the point (10, 4)?
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Dec 14, 2017
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What is the equation of the line perpendicular to 2x − 5y = −35 that contains the point (10, 4)?
Mathematics
high-school
Taeeun Kim
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Taeeun Kim
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I left the equation in the gradient-intercept form which is just the form where the 'y' variable in the equation is with a coefficient of 1.... Hope you can see the picture though.
Chen Dachao
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Dec 16, 2017
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Chen Dachao
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perpendicular has slope that multiplies to -1 in other sloope
thsi one
2x-5y=-35
-5y=-2x-35
y=2/5x+7
slope=2/5
2/5 times -5/2=-1
y=-5/2x+b
findn b
(10,4)
(x,y)
4=-5/2(10)+b
4=-25+b
21=b
y=-5/2x+21
2y=-5x+42
5x+2y=42
OussamaLord
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Dec 19, 2017
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OussamaLord
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