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The molar heat of fusion for water is 6.01 kJ/mol. How much energy is released when 36.8 g of water freezes at its freezing point?

2 Answers

2 votes

Answer:

12.3 kJ

Step-by-step explanation:

User Shparekh
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The answer there is 12.3 kJ. First you have to calculate the amount of heat released (n) based on the given. Just multiply 36.8 grams of water to a mole of water per 18.015 grams, which will give you 2.04 moles of H2O. Using the formula heat released (q) = number for moles of the substance (n) multiplied to the molar enthalpy of fusion of the substance (H), you will have the (2.04 mole)(-6.01 kJ/mole), giving you an answer of -12.3kJ.

User Sanjeev Sangral
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