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Area circumstances circle and square 5 in 6 in 4 in PLEASE HELP PLEASE!

Area circumstances circle and square 5 in 6 in 4 in PLEASE HELP PLEASE!-example-1
User Kala
by
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1 Answer

8 votes

Answer:

20.24in^2

Explanation:


\pir^2

3.14 times 16in

that is 50.24

6 times 5 = 30

50.24 - 30= 20.24

User Sampgun
by
6.9k points