Question

A 3.28 L solution is prepared by dissolving 535 g CaCl2 in water. The molar mass of CaCl2 is 110.98 g. What is the morality of the solution?

Answer 1

1.47 mol/L

Step-by-step explanation:

Molarity is given as,

Molarity = Moles / Vol in L ------- (1)

Moles of CaCl₂,

Moles = Mass / M.Mass

Moles = 535 g / 110.98 g/mol

Moles = 4.82 mol

Now, putting values in eq. 1.

Molarity = 4.82 mol / 3.28 L

Molarity = 1.47 mol/L