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What are the solutions for the equation 2z^2+4z+2=0
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What are the solutions for the equation 2z^2+4z+2=0

User MDaniyal
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7.8k points

1 Answer

3 votes
undistribute 2
2(z^2+2z+1)=0
factor
2(z+1)(z+1)=0
se to zero
2=0 false
z+1=0
z=-1


solution is z=-1
User Iiridayn
by
8.3k points
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