Question

Solve 2x2 + 12x − 14 = 0 by completing the square, options: A. 2(x + 6)2 = 26; x = −6 + square root 13, x = −6 − square root 13 B. 2(x + 6)2 = 20; x = −6 + square root 20, x = −6 − square root 20 C. 2(x + 3)2 = 32; x = 1, x = −7 D. 2(x + 3)2 = 32; x = 13, x = 19

Answer 1

the answer is c: 2(x + 3)2 = 32; x = 1, x = −7

Explanation:

I took the test

Answer 2

I just solved this one
anothe way is undistribute the 2 first and move -14 to side
2(x^2+6x)-14=0
comlete the squer inside and add negative
2(x^2+6x+9-9)-14=0
factor perfect square
2((x+3)^2-9)-14=0
distribute
2(x+3)^2-18-14=0
2(x+3)^2-32=0
add 32 both sides
2(x+3)^2=32
divide 2
(x+3)^2=16
sqrt both sides
x+3=+/-4
minus 3
x=-4-3 or 4-3
x=1 or -7

answer is C