Question

If h(x)=x²-5x+7, find the value of h(2), and h(-5)

Answer 1

h(2) =
`2^(2)`-5(2)+7 = 1

h(-5) =
`(-5)^(2)`-5(-5)+7 = 7

Explanation:

Answer 2

h(2)= (2)^2 -5(2)+7
2^2 is 4
-5x2 is -10
+7
So 4-10+7
=1
h(2)=1

h(-5)=(-5)^2 -5(-5)+7
-5^2 is 25
-5x-5 is 25
+7
So h(-5)=57