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If h(x)=x²-5x+7, find the value of h(2), and h(-5)
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15 votes
If h(x)=x²-5x+7, find the value of h(2), and h(-5)

User XGouchet
by
8.2k points

2 Answers

12 votes

Answer:

h(2) =
2^(2)-5(2)+7 = 1

h(-5) =
(-5)^(2)-5(-5)+7 = 7

Explanation:

User Bachi
by
7.3k points
2 votes
h(2)= (2)^2 -5(2)+7
2^2 is 4
-5x2 is -10
+7
So 4-10+7
=1
h(2)=1

h(-5)=(-5)^2 -5(-5)+7
-5^2 is 25
-5x-5 is 25
+7
So h(-5)=57
User Mihai Timar
by
7.6k points
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