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Vitellium (Vi) has the following composition:Vi-188: 187.9122 amu; 10.861%Vi-191: 190.9047 amu; 12.428%Vi-193: 192.8938 amu; 76.711%Based on this data, what can you predict about the average atomic mass
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Vitellium (Vi) has the following composition:Vi-188: 187.9122 amu; 10.861%Vi-191: 190.9047 amu; 12.428%Vi-193: 192.8938 amu; 76.711%Based on this data, what can you predict about the average atomic mass of vitellium?

User Kinkajou
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1 Answer

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10.861% / 100 = 0.10861

12.428 % / 100 = 0.12428

(0.10861 * 187.9122) + (0.12428 * 190.9407) + (0.76711 x 192.8938)

= 192.1100 amu .

hope this helps!

User Mikayil Abdullayev
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8.8k points
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