Question

4.16 Unit Test: Right Triangle Trigonometry - Part 1What is the value of x?0404/24720845°08V2

Answer 1

we have that

`\sin (45^o)=\frac{4\sqrt[]{2}}{x}`

by opposite side divided by the hypotenuse

Remember that

`\sin (45^o)=\frac{\sqrt[]{2}}{2}`

substitute

`\frac{\sqrt[]{2}}{2}=\frac{4\sqrt[]{2}}{x}`

solve for x

`x=\frac{8\sqrt[]{2}}{\sqrt[]{2}}`

simplify

x=8