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A square has a perimeter of 20 cm what is the length of its diagonal rounded to the nearest tenth

User ZixiCat
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2 Answers

2 votes
multiply the length of one side by the square root of 2.

20√2 = 28.28
Rounded to the nearest tenth:
28.28
→28.3

28.3 is the final answer
User Cheol
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7.3k points
2 votes
-- All 4 sides of a square are the same length.
The perimeter is 20 cm.
So each side is (20/4) = 5 cm.

-- If you cut the square along its diagonal, and throw one piece away ...

You have a right triangle.
The legs are sides of the square ... 5 cm each.
The hypotenuse is the diagonal of the square, which you have to find.

-- The (hypotenuse of any right triangle)²

= (the length of one leg)² + (the length of the other leg)² .

(Diagonal)² = (5 cm)² + (5 cm)²

(Diagonal)² = (25 cm²) + (25 cm²)

(Diagonal)² = (50 cm²)

Diagonal = √(50 cm²) = 7.07 cm

or 7.1 cm rounded to the nearest tenth.
User AnotherHowie
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