Question

In a study by the Department of Transportation, there were a total of 95 drivers that were pulled over for speeding. Out of those 95 drivers, 33 were men who were ticketed, 8 were men who were not ticketed, 7 were women who were ticketed, and 47 were women who were not ticketed. Suppose one person was chosen at random.

1. What is the probability that the selected person is someone who was not ticketed, given it is a woman?
2. What is the probability that the selected person is someone who was not ticketed, given it is a man?
Enter your answers as whole numbers or fractions in lowest terms.

Answer 1

1) 47/54 probability that the selected person is someone who was not ticketed, given it is a woman.

2) 8/41 probability that the selected person is someone who was not ticketed, given it is a man.

Explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

1. What is the probability that the selected person is someone who was not ticketed, given it is a woman?

7 + 47 = 54 total woman

47 were not ticketed. So

`p = (47)/(54)`

47/54 probability that the selected person is someone who was not ticketed, given it is a woman.

2. What is the probability that the selected person is someone who was not ticketed, given it is a man?

33 + 8 = 41 men.

8 were not ticketed. So

`p = (8)/(41)`

8/41 probability that the selected person is someone who was not ticketed, given it is a man.