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4 votes
What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405?

11,097
11,508
11,919
12,330

2 Answers

0 votes

Answer:

11,919

Explanation:

took the test

User TechArcSri
by
8.1k points
1 vote
Given:
58 - term
first term : 6
last term : 405

Sum = n * (a+l)/2
Sum = 58 * (6 + 405)/2
Sum = 58 * 411/2
Sum = 58 * 205.5
Sum = 11,919
User Sandeep Mukherjee
by
8.1k points

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