What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405? 11,097 11,508 11,919 12,330

asked Mar 22, 2017 172k views

4 votes

What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405?

11,097
11,508
11,919
12,330

6.7k points

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0 votes

Answer:

11,919

Explanation:

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TechArcSri answered Mar 23, 2017

7.0k points

1 vote

Given:
58 - term
first term : 6
last term : 405

Sum = n * (a+l)/2
Sum = 58 * (6 + 405)/2
Sum = 58 * 411/2
Sum = 58 * 205.5
Sum = 11,919

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