Question

Ilya and Anya each can run at a speed of 7.50 mph and walk at a speed of 4.00 mph. They set off together on a route of length 5.00 miles . Anya walks half of the distance and runs the other half, while Ilya walks half of the time and runs the other half.

Required:
a. How long does it take Anya to cover the distance of 5.00 ?
b. Find Anya's average speed.
c. How long does it take Ilya to cover the distance?

Answer 1

`T_A=0.93hours`

`S_A=5.23mph`

`T_l=0.87hour`

Step-by-step explanation:

From the question we are told that

Run speed of Ilya and Anya
`S_r=7.50mph`

Walk speed of Ilya and Anya
`S_w=4.00mph`

Total distance
`T_d=5.00miles`

Anya Walks 1/2d and runs 1/2d

ilya walks 1/2t and runs 1/2d

Generally the distance walked by Ilay k is mathematically given by

Since ilya walks 1/2t and runs 1/2t

Therefore

`(k)/(4)=(5-k)/(7.5)`

`k=1.7miles`

Therefore llay runing distance is m

`m=5-1.7\\m=3.3mile`

a)Generally the Time walked by Anya
`T_A` is mathematically given by

Anya Walks 1/2d and runs 1/2d

Therefore

`t=(2.5)/(4.)`

`t_1=0.6hours`

`t=(2.5)/(7.5)`

`t_2=0.33hours`

`T_A=0.6+0.33\\`

`T_A=0.93hours`

b)Generally the average speed of Anya S_A is mathematically given as

`S_A=(Distance)/(T_t)`

`S_A=(5.0)/(0.93)`

`S_A=5.23mph`

Generally the time taken b y llay
`T_l` is mathematically given by

`T_l=2t`

`T_l=2*((1.7)/(4))`

`T_l=0.87hour`