Question

2x+4y=12 y=0.25x-3 What is the solution to the system of equations?

(–1, 8)
(8, –1)
(5,1/2) 0r (1/2,5)

Answer 1

{ 2 x + 4 y = 12
y = 0.25 x -3

Arrange equation variables of elimination :

{ 2 x + 4 y = 12
-0.25 x + y = - 3

Multiply ( -0.25 x +y = - 3 ) by 8 :

8y - 2 x = - 24

{ 2 x + 4y = 12
-2x + 8y = -24
----------------------
12 y = -12

y = - 12 / 12

y = - 1

For x :

2 x + 4y = 12

2 x + 4 ( - 1 ) = 12

2 x - 4 = 12

2 x = 12 + 4

2 x = 16

x = 16 / 2

x = 8

x = 8 and y = - 1 => ( 8 , - 1 )

Answer b

hope this helps!