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What is the acceleration along the ground of a 10 kg wagon when its pulled with a force of 44 N at an angle of 35° above the horizontal?

A. 0.23 m/s
B. 0.28 m/s
C. 2.52 m/s
D. 3.60 m/s

2 Answers

4 votes
The correct answer is D I hope this helps you i just took the test and got it right have an amazing day

User Jette
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Answer:

D. 3.60 m/s^2

Step-by-step explanation:

First of all, we need to find the horizontal force acting on the wagon, which is given by:


F_x = F cos \theta=(44 N)(cos 35^(\circ))=36.0 N

And now we can calculate the wagon's acceleration by using Newton's second law:


a=(F_x)/(m)=(36.0 N)/(10 kg)=3.60 m/s^2

User Akeem
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