Question

How many moles of glucose (C6H12O6) are in 6.0 liters of a 3.5 M C6H12O6 solution?

21 moles
9.5 moles
3.5 moles
1.7 moles

Answer 1

Molarity = number of moles / volume in L

3.5 = n / 6.0

n = 3.5 * 6.0

n = 21 moles

answer A

hope this helps!

Answer 2

Answer : The number of moles of glucose are, 21 moles

Explanation : Given,

Volume of solution = 6.0 L

Molarity of glucose solution = 3.5 M = 3.5 mole/L

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

`Molarity=\frac{\text{Moles of glucose}}{\text{Volume of solution}}`

Now we put all the given values in this formula, we get the number of moles of glucose.

`3.5mole/L=\frac{\text{Moles of glucose}}{6.0L}`

`\text{Moles of glucose}=21moles`

Therefore, the number of moles of glucose are, 21 moles