Answer:
20 $50 bills
8 $10 bills
Explanation:
Find how many $10 and $50 bills are in the cash register.
Make a systems of equations:
t = Amount of $10 bills
f = Amount of $50 bills
10t + 50f = 1080
t + f = 28
Lets solve for $50 bills first:
10t + 50f = 1080
-10(t + f = 28) = -10t - 10f = -280
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Solve for f:
10t + 50f = 1080
-10t - 10f = -280
40f = 800
Divide both sides by 40.
f = 20
There are 20 $50 bills.
Now we need to find how many $10 bills are in the register.
Plug in 20 to "f" in one of the equations and solve for "t".
Solve:
t + 20 = 28
Subtract 20 from both sides.
t = 8
There are 8 $10 bills.
Your answer should be:
20 $50 bills
8 $10 bills