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Ryan Russon · Answer 1 · 2017-05-02T10:50:26+0000

remember a^2-b^2=(a-b)(a+b) 16=4^2 x^4=(x^2)^2 so 16x^4-1=(4x^2)^2-(1)^2=(4x^2-1)(4x^2+1) and the 4x^2-1 can be further factored (2x)^2-(1)^2=(2x-1)(2x+1) factoref rom is (4x^2+1)(2x+1)(2x-1) D is answer

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