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Polygon ABCDE rotates 45° clockwise about point F to produce polygon FGHIJ as shown. What is mBCD?

User Henry Neo
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2 Answers

7 votes

Answer:

127°

Explanation:

The tranformstion is a rotation 45° clockwise.

Notice that this is a rigid transformation, which means it won't change the size or shape of the original figure, in other words, those figures will be similar.

Having said that angle BCD corresponds to angle GHI, that is


\angle BCD \cong \angle GHI

So, if
m\angle GHI = 127\°, then
m\angle BCD = 127\°, becasue they are congruent.

Therefore, the answer is 127°.

Polygon ABCDE rotates 45° clockwise about point F to produce polygon FGHIJ as shown-example-1
User Eljah
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8.2k points
6 votes
The correct answer for the question that is being presented above is this one: 127 degrees.

The order of letters is important.

Since polygon ABCDE is rotated to produce polygon FGHIJ, then image of A is F, image of B is G, etc...

And since rotation preserves the shape, then
m∠BCD = m∠GHI = 127°
User Leela
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8.0k points

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