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PLZ HELP 10 PTS!!

Jill jumped 6 1/3 feet in the long-jump event. Jill best friend jumped 6 5/7 feet. How much farther did Jill's best friend jumped? Describe in words the process you used to solve the problem.

2 Answers

4 votes

Answer:

Kates best friend jumped 8/21 feet more than kate did

Explanation:

First to find the difference between two fractions they need a common denominator, 21 works for this. Then the actual fractions need to match the denominator. 7/21 and 15/21 are our new frations. Then when subtraction you subtract the numerators, the answer to that is 8/21 after simplifying (in this case you cant) you subtract the whole numbers, 6 – 6 = 0 the add the whole and fraction together. Kates best friend jumped 8/21 more feet than kate did.

User Pat Newell
by
6.4k points
7 votes

Answer:

Jill's best friend jumped 8/21 feet further than Jill.

Explanation:

we have that

Jill jumped 6 1/3 feet

Jill best friend jumped 6 5/7 feet

To find out how much farther did Jill's best friend jumped, subtract the length that Jill jumped from the length that Jill best friend jumped


6(5)/(7)-6(1)/(3)

but first convert mixed number to improper fraction


6(5)/(7)\ ft=(6*7+5)/(7)=(47)/(7)\ ft


6(1)/(3)\ ft=(6*3+1)/(3)=(19)/(3)\ ft

substitute the values


(47)/(7)-(19)/(3)=(47*3-7*19)/(21)=(8)/(21)\ ft

therefore

Jill's best friend jumped 8/21 feet further than Jill.

User Selvagsz
by
6.6k points
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